24x^2+2x=15

Solution for 24x^2+2x=15 equation:

24x^2+2x=15

We move all terms to the left:

24x^2+2x-(15)=0

a = 24; b = 2; c = -15;
Δ = b2-4ac
Δ = 22-4·24·(-15)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*24}=\frac{-40}{48}
=-5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*24}=\frac{36}{48}
=3/4
$